Physics Circle home Student Login

Home›Chapters›Motion in One Dimension PYQs›Motion Under Gravity›Question 58

JEE Main 2002 (AIEEE) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2002 (AIEEE)

Q58JEE Main 2002 · AIEEEEasy

Motion Under Gravity

From a building two balls A and B are thrown such that A is thrown upwards and B downwards ( both vertically with the same speed ). If vA and vB are their respective velocities on reaching the ground, then

Show answer and solution

Answer: (b)

  1. Ball A comes back to the throwing point with the same speed uu, now moving down, just like B.
  2. Both then fall the same height hh: v2=u2+2ghv^2 = u^2 + 2gh for each.
  3. So the answer is (b) vA=vBv_A = v_B.
Report a mistake

More questions on Motion Under Gravity