Combination of Capacitors question from JEE Main 2026 (4 Apr, Shift 2)

Answer: (a)

1. The top wire puts A and the node between $C_2$ and $C_3$ at the same potential.
2. So $C_1$ and $C_2$ are in parallel between A and the node after $C_1$: $1 + 1 = 2\ \mu\text{F}$; $C_3$ is directly between A and B.
3. $C_4$ joins that node to B: $(C_1 \parallel C_2)$ in series with $C_4$ $= \frac{2\times 2}{4} = 1\ \mu\text{F}$.
4. $C_{AB} = 1 + C_3 = 1 + 1 = 2\ \mu\text{F}$
5. So the answer is (a) 2.