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JEE Main 2025 (4 Apr, Shift 2) · Combination of Resistors

Combination of Resistors question from JEE Main 2025 (4 Apr, Shift 2)

Q9JEE Main 2025 · 4 APR · SHIFT 2Medium

Combination of Resistors

From the combination of resistors with resistances values R1=R2=R3=5 ΩR_1 = R_2 = R_3 = 5\ \Omega and R4=10 ΩR_4 = 10\ \Omega, which of the following combination is the best circuit to get an equivalent resistance of 6 Ω6\ \Omega?

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Answer: (b)

  1. (a) all parallel: 1R=35+110⇒R≈1.43 Ω\dfrac{1}{R} = \dfrac{3}{5} + \dfrac{1}{10} \Rightarrow R \approx 1.43\ \Omega.
  2. (b) (R1+R2)∥(R3+R4)=10∥15=15025=6 Ω(R_1 + R_2) \parallel (R_3 + R_4) = 10 \parallel 15 = \dfrac{150}{25} = 6\ \Omega
  3. (c) 5∥10∥10=2.5 Ω5 \parallel 10 \parallel 10 = 2.5\ \Omega; (d) 20∥5=4 Ω20 \parallel 5 = 4\ \Omega.
  4. So the answer is (b).
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