From the given transfer characteristic of a transistor in CE configuration, the value of power gain of this configuration is 10x, for RB = 10 kΩ, and RC = 1 kΩ. The value of x is __________. Numerical answer type. Work it out, then open the answer.

Answer: 3. From the graph: β = (Δ IC)/(Δ IB) = ((20 - 10) mA)/((200 - 100)) = 100 Power gain: Ap = β² (RC)/(RB) = 10⁴ × (1 kΩ)/(10 kΩ) = 10³ So x = 3.

From the given transfer characteristic of a transistor in CE… | JEE Main 2023 (13 Apr, Shift 1)

Q50JEE Main 2023 · 13 APR · SHIFT 1Medium

Junction Transistor

From the given transfer characteristic of a transistor in $\text{CE}$ configuration, the value of power gain of this configuration is $10^{x}$ , for $\mathrm{R}_{\mathrm{B}} = 10\text{ k}\Omega$ , and $\mathrm{R}_{\mathrm{C}} = 1\text{ k}\Omega$ . The value of $x$ is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

From the graph: $\beta = \dfrac{\Delta I_C}{\Delta I_B} = \dfrac{(20 - 10)\ \text{mA}}{(200 - 100)\ \mu\text{A}} = 100$
Power gain: $A_p = \beta^2 \dfrac{R_C}{R_B} = 10^4 \times \dfrac{1\ \text{k}\Omega}{10\ \text{k}\Omega} = 10^3$
So $x = 3$ .

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