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JEE Main 2022 (24 Jun, Shift 1) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (24 Jun, Shift 1)

Q22JEE Main 2022 · 24 JUN · SHIFT 1Easy

Motion Under Gravity

From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in ____________ s.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

For a tower, time to fall from rest $t = \sqrt{t_1 t_2}$ , where $t_1, t_2$ are the up-throw and down-throw times with the same speed.
$t = \sqrt{6 \times 1.5} = \sqrt{9} = 3$ s
So the answer is 3 s.

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