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JEE Main 2025 (2 Apr, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (2 Apr, Shift 2)

Q15JEE Main 2025 · 2 APR · SHIFT 2Easy

Units & Dimensions

Given a charge q, current I and permeability of vacuum μo\mu_o. Which of the following quantity has the dimension of momentum?

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Answer: (d)

  1. [μ0]=MLT−2A−2[\mu_0] = \mathrm{MLT^{-2}A^{-2}} (from F/l=μ0I2/2πdF/l = \mu_0 I^2/2\pi d), [q]=AT[q] = \mathrm{AT}, [I]=A[I] = \mathrm{A}.
  2. [qμ0I]=AT⋅MLT−2A−2⋅A=MLT−1[q\mu_0 I] = \mathrm{AT}\cdot\mathrm{MLT^{-2}A^{-2}}\cdot\mathrm{A} = \mathrm{MLT^{-1}}
  3. This is the dimension of momentum.
  4. So the answer is (d) qμ0Iq\mu_0 I.
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