Given below are the two circuits, choose the correct option. (a) At resonance, current in (B) is less than that in (A) (b) The r.m.s. current in (B) can be larger than that in (A) (c) The r.m.s. current in (A) is always equal to that in (B) (d) The r.m.s. current in (B) can never be larger than that in (A)

Answer: (d). IA = V/R and IB = V/Z with Z = √(R² + (XL - XC)²) ≥ R. So IB ≤ IA; they are equal only at resonance, never IB > IA. At 50 Hz, XC = 12π×50×0.4×10⁻⁶ ≈ 7960 Ω XL ≈ 12.6 Ω, so here IB < IA. So the answer is (d) the r.m.s. current in (B) can never be larger than that in (A).

Given below are the two circuits, choose the correct option. | MHT CET 2026 (20 Apr, Shift 2)

Q20MHT CET 2026 · 20 APR · SHIFT 2Medium

Resonance, Bandwidth & Q Factor

Given below are the two circuits, choose the correct option.

Show answer and solution

Answer: (d)

$I_A = \frac{V}{R}$ and $I_B = \frac{V}{Z}$ with $Z = \sqrt{R^2 + (X_L - X_C)^2} \ge R$ .
So $I_B \le I_A$ ; they are equal only at resonance, never $I_B > I_A$ .
At 50 Hz, $X_C = \frac{1}{2\pi\times50\times0.4\times10^{-6}} \approx 7960\ \Omega \gg X_L \approx 12.6\ \Omega$ , so here $I_B < I_A$ .
So the answer is (d) the r.m.s. current in (B) can never be larger than that in (A).

Report a mistake

Resonance, Bandwidth & Q Factor question from MHT CET 2026 (20 Apr, Shift 2)

More questions on Resonance, Bandwidth & Q Factor