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JEE Main 2022 (25 Jun, Shift 2) · Comparing Two Projectiles

Comparing Two Projectiles question from JEE Main 2022 (25 Jun, Shift 2)

Q17JEE Main 2022 · 25 JUN · SHIFT 2Medium

Comparing Two Projectiles

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Two identical balls A and B thrown with same velocity 'u' at two different angles with horizontal attained the same range R. If A and B reached the maximum height h1 and h2 respectively, then R=4h1h2R = 4\sqrt{h_1 h_2}

Reason R: Product of said heights.

h1h2=(u2sin⁡2θ2g)⋅(u2cos⁡2θ2g)h_1 h_2 = \left(\frac{u^2 \sin^2\theta}{2g}\right) \cdot \left(\frac{u^2 \cos^2\theta}{2g}\right)

Choose the correct answer:

Show answer and solution

Answer: (a)

  1. Same range means angles θ\theta and 90∘−θ90^\circ - \theta, so h1=u2sin⁡2θ2gh_1 = \frac{u^2\sin^2\theta}{2g}, h2=u2cos⁡2θ2gh_2 = \frac{u^2\cos^2\theta}{2g}: R is true.
  2. h1h2=u4sin⁡2θcos⁡2θ4g2h_1 h_2 = \frac{u^4\sin^2\theta\cos^2\theta}{4g^2} and R2=4u4sin⁡2θcos⁡2θg2=16h1h2R^2 = \frac{4u^4\sin^2\theta\cos^2\theta}{g^2} = 16h_1 h_2
  3. So R=4h1h2R = 4\sqrt{h_1 h_2}: A is true and follows directly from R.
  4. So the answer is (a).
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