Given below are two statements: one is labelled as Assertion A and… | JEE Main 2023 (12 Apr, Shift 1)

Q58JEE Main 2023 · 12 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

Assertion A: If an electric dipole of dipole moment $30 \times 10^{-5}\text{ C m}$ is enclosed by a closed surface, the net flux coming out of the surface will be zero.

Reason R: Electric dipole consists of two equal and opposite charges.

In the light of the above statements, choose the correct answer from the options given below.

Show answer and solution

Answer: (d)

A dipole has charges $+q$ and $-q$ , so net enclosed charge is zero.
By Gauss's law the net flux is zero, so A is true.
R is true and is exactly why the enclosed charge is zero.
So the answer is (d).

Report a mistake

More questions on Electric Flux & Gauss's Law

A charge 17.7 × 10⁻⁴ C is distributed uniformly over a large sheet of area 200 m². The…MHT CET 2023 (14 May, Shift 2)
The electric field intensity on the surface of a solid charged sphere of radius ' r ' and…MHT CET 2023 (14 May, Shift 1)
Graphical variation of electric field due to a uniformly charged insulating solid sphere…JEE Main 2023 (8 Apr, Shift 1)
Let σ be the uniform surface charge density of two infinite thin plane sheets shown in…JEE Main 2023 (1 Feb, Shift 1)
Which of the following statements is 'WRONG' for the conductors?MHT CET 2023 (13 May, Shift 1)
As shown in the figure, a point charge Q is placed at the centre of conducting spherical…JEE Main 2023 (30 Jan, Shift 2)
A cubical volume is bounded by the surfaces x = 0, x = a, y = 0, y = a, z = 0, z = a. The…JEE Main 2023 (1 Feb, Shift 2)
Expression for an electric field is given by E = 4000x²i V/m. The electric flux through…JEE Main 2023 (31 Jan, Shift 1)

Electric Flux & Gauss's Law question from JEE Main 2023 (12 Apr, Shift 1)

More questions on Electric Flux & Gauss's Law