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JEE Main 2024 (27 Jan, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2024 (27 Jan, Shift 2)

Q48JEE Main 2024 · 27 JAN · SHIFT 2Easy

Electric Potential & Equipotentials

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Work done by electric field on moving a positive charge on an equipotential surface is always zero.

Reason (R): Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below:

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Answer: (a)

  1. A: on an equipotential surface ΔV=0\Delta V = 0, so W=qΔV=0W = q\Delta V = 0. True.
  2. R: field lines are normal to equipotentials. True.
  3. Since F⃗\vec F is perpendicular to the displacement along the surface, W=F⃗⋅ds⃗=0W = \vec F\cdot d\vec s = 0, so R explains A.
  4. So the answer is (a).
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