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JEE Main 2025 (22 Jan, Shift 2) · Simple Pendulum

Simple Pendulum question from JEE Main 2025 (22 Jan, Shift 2)

Q23JEE Main 2025 · 22 JAN · SHIFT 2Easy

Simple Pendulum

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): A simple pendulum is taken to a planet of mass and radius, 4 times and 2 times, respectively, that of the Earth. The time period of the pendulum remains same on earth and the planet.

Reason (R): The mass of the pendulum remains unchanged at Earth and the other planet. In the light of the above statements, choose the correct answer from the options given below:

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Answer: (d)

  1. g=GMR2g = \frac{GM}{R^2}; on the planet g′=G(4M)(2R)2=gg' = \frac{G(4M)}{(2R)^2} = g.
  2. Same gg gives the same TT: (A) true.
  3. Mass of the bob does not change: (R) true, but TT does not depend on mass, so (R) does not explain (A).
  4. So the answer is (d).
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