Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Photoelectric Experiment: Intensity, Stopping Potential & Graphs›Question 14

JEE Main 2025 (29 Jan, Shift 1) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2025 (29 Jan, Shift 1)

Q14JEE Main 2025 · 29 JAN · SHIFT 1Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Emission of electrons in photoelectric effect can be suppressed by applying a sufficiently negative electron potential to the photoemissive substance.

Reason (R): A negative electric potential, which stops the emission of electrons from the surface of a photoemissive substance, varies linearly with frequency of incident radiation.

In the light of the above statements, choose the most appropriate answer from the options given below:

Show answer and solution

Answer: (b)

  1. A: a sufficiently negative (retarding) potential stops even the fastest electrons, so the photocurrent becomes zero. A is true.
  2. R: V0=heν−ϕeV_0 = \dfrac{h}{e}\nu - \dfrac{\phi}{e}, which is linear in ν\nu. R is true.
  3. R only describes how V0V_0 varies with frequency; it does not explain why emission can be suppressed.
  4. So the answer is (b).
Report a mistake

More questions on Photoelectric Experiment: Intensity, Stopping Potential & Graphs