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JEE Main 2025 (29 Jan, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2025 (29 Jan, Shift 2)

Q67JEE Main 2025 · 29 JAN · SHIFT 2Medium

Thermodynamic Processes

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): With the increase in the pressure of an ideal gas, the volume falls off more rapidly in an isothermal process in comparison to the adiabatic process.

Reason (R): In isothermal process, PV = constant, while in adiabatic process PVγPV^{\gamma} = constant. Here γ\gamma is the ratio of specific heats, P is the pressure and V is the volume of the ideal gas. In the light of the above statements, choose the correct answer from the options given below:

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Answer: (d)

  1. Isothermal: PV=PV = const ⇒dVdP=−VP\Rightarrow \dfrac{dV}{dP} = -\dfrac{V}{P}.
  2. Adiabatic: PVγ=PV^{\gamma} = const ⇒dVdP=−VγP\Rightarrow \dfrac{dV}{dP} = -\dfrac{V}{\gamma P}.
  3. Since γ>1\gamma > 1, volume falls faster with pressure in the isothermal process, so (A) is true.
  4. (R) gives exactly the relations used, so it explains (A). So the answer is (d).
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