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JEE Main 2025 (8 Apr, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2025 (8 Apr, Shift 2)

Q27JEE Main 2025 · 8 APR · SHIFT 2Easy

Electric Potential & Equipotentials

Given below are two statements: one is labelled as Assertion A\mathbf{A} and the other is labelled as Reason R\mathbf{R}

Assertion A: Work done in moving a test charge between two points inside a uniformly charged spherical shell is zero, no matter which path is chosen.

Reason R: Electrostatic potential inside a uniformly charged spherical shell is constant and is same as that on the surface of the shell.

In the light of the above statements, choose the correct answer from the options given below.

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Answer: (b)

  1. R: inside a shell E=0E = 0, so V=kQRV = \frac{kQ}{R} everywhere inside, same as the surface. True.
  2. A: W=q(VB−VA)=0W = q(V_B - V_A) = 0 since VA=VBV_A = V_B, for any path. True.
  3. R directly gives A, so the answer is (b).
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