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JEE Main 2022 (28 Jul, Shift 2) · Combination of Resistors

Combination of Resistors question from JEE Main 2022 (28 Jul, Shift 2)

Q39JEE Main 2022 · 28 JUL · SHIFT 2Medium

Combination of Resistors

Given below are two statements:

Statement I: A uniform wire of resistance 80 Ω80\ \Omega is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be 5 Ω5\ \Omega.

Statement II: Two resistances 2R and 3R are connected in parallel in an electric circuit. The value of thermal energy developed in 3R and 2R will be in the ratio 3:23 : 2.

In the light of the above statements, choose the most appropriate answer from the option given below

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Answer: (c)

  1. Statement I: each part is 20 Ω20\ \Omega; four in parallel give 204=5 Ω\dfrac{20}{4} = 5\ \Omega. True.
  2. Statement II: in parallel VV is the same, so H=V2tR∝1RH = \dfrac{V^2 t}{R} \propto \dfrac{1}{R}.
  3. H3R:H2R=13:12=2:3H_{3R} : H_{2R} = \dfrac{1}{3} : \dfrac{1}{2} = 2 : 3, not 3:23 : 2. False.
  4. So the answer is (c).
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