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MHT CET 2026 (11 Apr, Shift 1) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2026 (11 Apr, Shift 1)

Q6MHT CET 2026 · 11 APR · SHIFT 1Easy

Acceleration Due to Gravity

Given below are two statements:

Statement I: Acceleration due to earth's gravity decreases as you go 'up' or 'down' from earth's surface.

Statement II: Acceleration due to earth's gravity is same at a height 'hh' and depths 'dd' from earth's surface, if h=dh = d.

In the light of above statements, choose the most appropriate answer from the options given below.

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Answer: (c)

  1. Statement I: gg is maximum at the surface; it falls going up (∝1/r2\propto 1/r^2) and going down (∝r\propto r). Correct.
  2. Statement II: gh≈g(1−2hR)g_h \approx g\left(1-\frac{2h}{R}\right), gd=g(1−dR)g_d = g\left(1-\frac{d}{R}\right), so for h=dh = d they are not equal. Incorrect.
  3. So the answer is (c).
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