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JEE Main 2026 (22 Jan, Shift 2) · Motion of Centre of Mass

Motion of Centre of Mass question from JEE Main 2026 (22 Jan, Shift 2)

Q1JEE Main 2026 · 22 JAN · SHIFT 2Easy

Motion of Centre of Mass

Given below are two statements:

Statement I: For a mechanical system of many particles total kinetic energy is the sum of kinetic energies of all the particles.

Statement II: The total kinetic energy can be the sum of kinetic energy of the center of mass w.r.t. the origin and the kinetic energy of all the particles w.r.t. the center of mass as the reference. In the light of the above statements, choose the correct answer from the options given below:

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Answer: (d)

  1. Statement I: kinetic energy is a scalar, so the total is the sum over all particles. True.
  2. Statement II: K=12Mvcm2+∑12mivi,cm2K = \frac{1}{2}Mv_{cm}^2 + \sum \frac{1}{2}m_i v_{i,cm}^2, i.e. KE of the CM plus KE relative to the CM. True.
  3. So the answer is (d) both statements are true.
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