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JEE Main 2023 (8 Apr, Shift 1) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from JEE Main 2023 (8 Apr, Shift 1)

Q15JEE Main 2023 · 8 APR · SHIFT 1Easy

Satellite Energy & Weightlessness

Given below are two statements:

Statement I: If EE be the total energy of a satellite moving around the earth, then its potential energy will be E2\frac{E}{2}.

Statement II: The kinetic energy of a satellite revolving in an orbit is equal to the half the magnitude of total energy EE.

In the light of the above statements, choose the most appropriate answer from the options given below

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Answer: (a)

  1. E=−GMm2rE = -\frac{GMm}{2r}, U=−GMmr=2EU = -\frac{GMm}{r} = 2E, so Statement I (U=E/2U = E/2) is wrong.
  2. K=GMm2r=∣E∣K = \frac{GMm}{2r} = |E|, not ∣E∣/2|E|/2, so Statement II is wrong.
  3. So the answer is (a) both statements are incorrect.
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