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JEE Main 2021 (25 Feb, Shift 2) · Law of Equipartition of Energy

Law of Equipartition of Energy question from JEE Main 2021 (25 Feb, Shift 2)

Q4JEE Main 2021 · 25 FEB · SHIFT 2Medium

Law of Equipartition of Energy

Given below are two statements:

Statement I: In a diatomic molecule, the rotational energy at a given temperature obeys Maxwell's distribution.

Statement II: In a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule.

In the light of the above statements, choose the correct answer from the options given below:

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Answer: (c)

  1. Statement I: true; rotational energies of molecules are distributed statistically (Maxwell–Boltzmann) like translational energies.
  2. Statement II: diatomic rotational energy =2×12kT=kT= 2\times\dfrac{1}{2}kT = kT, translational =32kT= \dfrac{3}{2}kT; not equal, so false.
  3. So the answer is (c) Statement I is true but Statement II is false.
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