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JEE Main 2025 (22 Jan, Shift 1) · Least Count, Vernier Callipers & Screw Gauge

Least Count, Vernier Callipers & Screw Gauge question from JEE Main 2025 (22 Jan, Shift 1)

Q11JEE Main 2025 · 22 JAN · SHIFT 1Medium

Least Count, Vernier Callipers & Screw Gauge

Given below are two statements:

Statement I: In a vernier callipers, one vernier scale division is always smaller than one main scale division.

Statement II: The vernier constant is given by one main scale division multiplied by the number of vernier scale divisions.

In the light of the above statements, choose the correct answer from the options given below.

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Answer: (b)

  1. Statement I: in a standard vernier NN VSD =(N−1)= (N-1) MSD, so 1 VSD is smaller than 1 MSD. True.
  2. Statement II: vernier constant =1 MSDN= \dfrac{1\text{ MSD}}{N} (divided by, not multiplied by, the number of VSD). False.
  3. So the answer is (b).
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