Physics Circle home Student Login

Home›Chapters›Kinetic Theory of Gases PYQs›Molecular Speeds & Maxwell Distribution›Question 53

JEE Main 2022 (28 Jul, Shift 1) · Molecular Speeds & Maxwell Distribution

Molecular Speeds & Maxwell Distribution question from JEE Main 2022 (28 Jul, Shift 1)

Q53JEE Main 2022 · 28 JUL · SHIFT 1Medium

Molecular Speeds & Maxwell Distribution

Given below are two statements:

Statement I: The average momentum of a molecule in a sample of an ideal gas depends on temperature.

Statement II: The rms speed of oxygen molecules in a gas is vv. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become 2v2v. In the light of the above statements, choose the correct answer from the options given below:

Show answer and solution

Answer: (d)

  1. Statement I: molecules move randomly in all directions, so average momentum is zero at every temperature. False.
  2. Statement II: vrms∝T/Mv_{rms} \propto \sqrt{T/M}; TT doubled and MM halved gives 4=2\sqrt4 = 2 times, i.e. 2v2v. True.
  3. So the answer is (d).
Report a mistake

More questions on Molecular Speeds & Maxwell Distribution