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JEE Main 2024 (4 Apr, Shift 1) · Pressure in a Fluid

Pressure in a Fluid question from JEE Main 2024 (4 Apr, Shift 1)

Q8JEE Main 2024 · 4 APR · SHIFT 1Medium

Pressure in a Fluid

Given below are two statements:

Statement I: When speed of liquid is zero everywhere, pressure difference at any two points depends on equation P1−P2=ρg(h2−h1)P_1 - P_2 = \rho g (h_2 - h_1).

Statement II: In ventury tube shown 2gh=v12−v222gh = v_1^2 - v_2^2

Figure

In the light of the above statements, choose the most appropriate answer from the options given below.

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Answer: (a)

  1. Statement I: for a fluid at rest, P1+ρgh1=P2+ρgh2P_1 + \rho g h_1 = P_2 + \rho g h_2, so P1−P2=ρg(h2−h1)P_1 - P_2 = \rho g(h_2 - h_1). Correct.
  2. Statement II: Bernoulli at the same level gives P1−P2=12ρ(v22−v12)P_1 - P_2 = \tfrac{1}{2}\rho(v_2^2 - v_1^2), and P1−P2=ρghP_1 - P_2 = \rho g h.
  3. So 2gh=v22−v122gh = v_2^2 - v_1^2, not v12−v22v_1^2 - v_2^2. Statement II is incorrect.
  4. So the answer is (a).
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