Given figure shows few data points in a photoelectric effect… | JEE Main 2020 (4 Sep, Shift 1)

Q59JEE Main 2020 · 4 SEP · SHIFT 1Medium

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Given figure shows few data points in a photoelectric effect experiment for a certain metal. The minimum energy for ejection of electron from its surface is:

(Planck's constant h = 6.62 × 10–34 J.s)

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Answer: (b)

Minimum energy = work function $= h\nu_0$ , where $\nu_0$ is where $V_{stop} = 0$ .
The data point B $(5.5, 0)$ gives $\nu_0 = 5.5 \times 10^{14}$ Hz.
$\phi = 6.62 \times 10^{-34} \times 5.5 \times 10^{14} = 3.64 \times 10^{-19}$ J
$\phi = \frac{3.64 \times 10^{-19}}{1.6 \times 10^{-19}} \approx 2.27$ eV
So the answer is (b) 2.27 eV.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from JEE Main 2020 (4 Sep, Shift 1)

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