Student Login

Home›Chapters›Atomic Structure PYQs›Hydrogen Spectrum & Spectral Series›Question 55

NEET 2016 (Phase 1) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from NEET 2016 (Phase 1)

Q55NEET 2016 · PHASE 1Easy

Hydrogen Spectrum & Spectral Series

Given the value of Rydberg constant is 107 m ${}^{-1}$ , the wave number of the last line of the Balmer series in hydrogen spectrum will be

Show answer and solution

Answer: (a)

Rydberg constant $R = 10^{7}\text{ m}^{-1}$ .
Last line of Balmer: $\bar{\nu} = \frac{R}{4} = 0.25 \times 10^{7}\text{ m}^{-1}$ .
So the answer is (a) $0.25 \times 10^{7}\text{ m}^{-1}$ .

Report a mistake

More questions on Hydrogen Spectrum & Spectral Series

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to…NEET 2015 (AIPMT)
Ratio of longest wave lengths corresponding to Lyman and Balmer series in hydrogen…NEET 2013
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of…NEET 2011 (AIPMT, Prelims)
When an electron does transition from n = 4 to n = 2, then emitted line spectrum will beNEET 2000 (AIPMT)
Which source is associated with a line emission spectrum?NEET 1993 (AIPMT)
Which one of the following spectral series of hydrogen atom lies in ultraviolet region?MHT CET 2026 (20 May, Shift 1)
The ratio of minimum wavelengths of Lyman and Balmer series will beMHT CET 2026 (13 May, Shift 1)
In Bohr's theory of hydrogen atom, in any series of spectral lines, wavelength of first…MHT CET 2026 (12 May, Shift 2)