Glass has refractive index μ with respect to air and the critical angle for a ray of light going from glass to air is θ. If a ray of light is incident from air on the glass with angle of incidence θ, corresponding angle of refraction is (a) sin ⁻¹(μ) (b) sin ⁻¹((1)/(μ²)) (c) sin ⁻¹((1)/(√(μ))) (d) sin ⁻¹(1/μ)

Answer: (b). Critical angle from glass to air: sin θ = 1/μ. Air to glass at incidence θ: 1·sin θ = μ sin r. sin r = (sin θ)/(μ) = (1)/(μ²). So the answer is (b) sin ⁻¹((1)/(μ²)).

Glass has refractive index μ with respect to air and the critical… | MHT CET 2019 (3 May, Shift 1)

Q43MHT CET 2019 · 3 MAY · SHIFT 1Medium

Total Internal Reflection

Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $\theta$ . If a ray of light is incident from air on the glass with angle of incidence $\theta$ , corresponding angle of refraction is

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Answer: (b)

Critical angle from glass to air: $\sin\theta = \frac{1}{\mu}$ .
Air to glass at incidence $\theta$ : $1\cdot\sin\theta = \mu \sin r$ .
$\sin r = \frac{\sin\theta}{\mu} = \frac{1}{\mu^2}$ .
So the answer is (b) $\sin^{-1}\left(\frac{1}{\mu^2}\right)$ .

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