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MHT CET 2025 (23 Apr, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2025 (23 Apr, Shift 2)

Q21MHT CET 2025 · 23 APR · SHIFT 2Medium

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Graph shows variation of stopping potential with frequency of incident radiation on a metal plate. The value of Planck's constant is [ $\mathrm{e} =$ charge on photoelectron]

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Answer: (c)

$eV = h\nu - \phi$ , so slope of $V$ vs $\nu$ $= \frac{h}{e}$ .
From points C and D: slope $= \frac{V_2 - V_1}{\nu_2 - \nu_1}$ .
$h = \frac{e(V_2 - V_1)}{\nu_2 - \nu_1}$
So the answer is (c).

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