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JEE Main 2023 (8 Apr, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2023 (8 Apr, Shift 1)

Q61JEE Main 2023 · 8 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

Graphical variation of electric field due to a uniformly charged insulating solid sphere of radius $R$ , with distance $r$ from the centre O is represented by:

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Answer: (d)

Inside ( $r < R$ ): $E = \dfrac{\rho r}{3\varepsilon_0} \propto r$ , a straight line from the origin.
Outside ( $r > R$ ): $E = \dfrac{Q}{4\pi\varepsilon_0 r^2} \propto \dfrac{1}{r^2}$ , a falling curve.
Maximum at $r = R$ , continuous there.
So the answer is (d).

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