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NEET 2001 (AIPMT) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2001 (AIPMT)

Q118NEET 2001 · AIPMTEasy

Law of Radioactive Decay

Half-life period of a radioactive substance is $6\text{ h}$ . After $24\text{ h}$ activity is $0.01\ \mu\text{C}$ , what was the initial activity?

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Answer: (d)

$n = \frac{24}{6} = 4$ half-lives.
$A_0 = A \times 2^4 = 0.01 \times 16 = 0.16\ \mu\text{C}$ .
So the answer is (d) $0.16\ \mu\text{C}$ .

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