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JEE Main 2023 (31 Jan, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2023 (31 Jan, Shift 2)

Q145JEE Main 2023 · 31 JAN · SHIFT 2Medium

Thermodynamic Processes

Heat energy of 735 J735\text{ J} is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:

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Answer: (c)

  1. Rigid diatomic (rotation, no vibration): Cv=52RC_v = \frac{5}{2}R, Cp=72RC_p = \frac{7}{2}R.
  2. At constant pressure ΔUQ=CvCp=57\frac{\Delta U}{Q} = \frac{C_v}{C_p} = \frac{5}{7}
  3. ΔU=735×57=525 J\Delta U = 735 \times \frac{5}{7} = 525\text{ J}
  4. So the answer is (c) 525 J525\text{ J}.
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