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NEET 1995 (AIPMT) · Heat Conduction

Heat Conduction question from NEET 1995 (AIPMT)

Q55NEET 1995 · AIPMTMedium

Heat Conduction

Heat is flowing through two cylindrical rods of the same material. The diameters of the rods are in the ratio 1:21 : 2 and the lengths in the ratio 2:12 : 1. If the temperature difference between the ends is same, then ratio of the rate of flow of heat through them will be

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Answer: (d)

  1. H∝AL∝d2LH \propto \frac{A}{L} \propto \frac{d^2}{L} (same material and ΔT\Delta T).
  2. H1H2=(12)2×12=18\frac{H_1}{H_2} = \left(\frac{1}{2}\right)^2 \times \frac{1}{2} = \frac{1}{8}
  3. So the answer is (d) 1:81:8.
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