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JEE Main 2026 (2 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2026 (2 Apr, Shift 1)

Q6JEE Main 2026 · 2 APR · SHIFT 1Easy

Thermodynamic Processes

Heat is supplied to a diatomic gas at constant pressure. Then the ratio of ΔQ:ΔU:ΔW\Delta Q : \Delta U : \Delta W is ______.

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Answer: (d)

  1. At constant pressure: ΔQ=nCpΔT\Delta Q = nC_p\Delta T, ΔU=nCvΔT\Delta U = nC_v\Delta T, ΔW=nRΔT\Delta W = nR\Delta T.
  2. Diatomic: Cp=72RC_p = \frac{7}{2}R, Cv=52RC_v = \frac{5}{2}R.
  3. ΔQ:ΔU:ΔW=72:52:1=7:5:2\Delta Q : \Delta U : \Delta W = \frac{7}{2} : \frac{5}{2} : 1 = 7 : 5 : 2
  4. So the answer is (d) 7 : 5 : 2.
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