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MHT CET 2026 (14 May, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (14 May, Shift 2)

Q18MHT CET 2026 · 14 MAY · SHIFT 2Medium

Thermodynamic Processes

Heat required to raise the temperature of 2 mol of an ideal gas at constant pressure from 25∘25^\circC to 35∘35^\circ C is 310 J. The amount of heat required to raise the temperature of the gas through the same range at constant volume is

(R=8.3R = 8.3 J/mol K)

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Answer: (b)

  1. Qp−Qv=n(Cp−Cv)ΔT=nRΔTQ_p - Q_v = n(C_p - C_v)\Delta T = nR\Delta T
  2. nRΔT=2×8.3×10=166 JnR\Delta T = 2 \times 8.3 \times 10 = 166\text{ J}
  3. Qv=310−166=144 JQ_v = 310 - 166 = 144\text{ J}
  4. So the answer is (b) 144144 J.
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