Hydrogen atom in ground state is excited by a monochromatic radiation of λ = 975 Å. Number of spectral lines in the resulting spectrum emitted will be (a) 3 (b) 2 (c) 6 (d) 10

Answer: (c). Photon energy E = (12400)/(975) ≈ 12.75 eV. En = -13.6 + 12.75 = -0.85 eV ⇒ n = 4. Number of lines = (n(n-1))/(2) = (4 × 3)/(2) = 6 So the answer is (c) 6.

Hydrogen atom in ground state is excited by a monochromatic radiation… | NEET 2014 (AIPMT)

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Transitions, Photon Emission & Excitation

Hydrogen atom in ground state is excited by a monochromatic radiation of $\lambda$ = 975 $\text{Å}$ . Number of spectral lines in the resulting spectrum emitted will be

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Answer: (c)

Photon energy $E = \frac{12400}{975} \approx 12.75$ eV.
$E_n = -13.6 + 12.75 = -0.85$ eV $\Rightarrow n = 4$ .
Number of lines $= \frac{n(n-1)}{2} = \frac{4 \times 3}{2} = 6$
So the answer is (c) 6.

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