Identical charges ( - q) are placed at each corners of cube of side b… | NEET 2002 (AIPMT)

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Electrostatic Potential Energy

Identical charges ( $-$ q) are placed at each corners of cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be

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Answer: (c)

Centre of a cube is at half the body diagonal from each corner: $r = \frac{\sqrt{3}b}{2}$ .
PE of $+q$ at the centre: $U = 8 \times \frac{(-q)(q)}{4\pi\varepsilon_0}\cdot\frac{2}{\sqrt{3}b}$
$U = -\frac{16q^2}{4\sqrt{3}\pi\varepsilon_0 b} = -\frac{4q^2}{\sqrt{3}\pi\varepsilon_0 b}$
So the answer is (c).

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Electrostatic Potential Energy question from NEET 2002 (AIPMT)

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