Identify the characteristics of an adiabatic process in a monoatomic gas. (A) Internal energy is constant. (B) Work done in the process is equal to the change in internal energy. (C) The product of temperature and volume is a constant. (D) The product of pressure and volume is a constant. (E) The work done to change the temperature from T₁ to T₂ is proportional to (T₂ - T₁). Choose the correct answer from the options given below: (a) (B), (D) only (b) (B), (E) only (c) (A), (C), (E) only (d) (A), (C), (D) only

Answer: (b). (A) False: T changes, so U changes. (B) True: Δ Q = 0, so |W| = |Δ U|. (C) False: TVγ-1 is constant, not TV. (D) False: PVγ is constant, not PV. (E) True: W = (nR(T₁ - T₂))/(γ - 1), proportional to the temperature change. So the answer is (b) (B), (E) only.

Identify the characteristics of an adiabatic process in a monoatomic… | JEE Main 2025 (2 Apr, Shift 2)

Q57JEE Main 2025 · 2 APR · SHIFT 2Easy

Thermodynamic Processes

Identify the characteristics of an adiabatic process in a monoatomic gas.

(A) Internal energy is constant.

(B) Work done in the process is equal to the change in internal energy.

(D) The product of pressure and volume is a constant.

(E) The work done to change the temperature from $T_1$ to $T_2$ is proportional to $(T_2 - T_1)$ . Choose the correct answer from the options given below:

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Answer: (b)

(A) False: $T$ changes, so $U$ changes.
(B) True: $\Delta Q = 0$ , so $|W| = |\Delta U|$ .
(C) False: $TV^{\gamma-1}$ is constant, not $TV$ . (D) False: $PV^{\gamma}$ is constant, not $PV$ .
(E) True: $W = \frac{nR(T_1 - T_2)}{\gamma - 1}$ , proportional to the temperature change.
So the answer is (b) (B), (E) only.

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