Logic Gates question from JEE Main 2014 (9 Apr, Shift 1)

Answer: (a)

1. First NAND: $\overline{A \cdot B}$.
2. Second NAND has its inputs shorted, so it acts as NOT: $Y = \overline{\overline{A \cdot B}} = A \cdot B$.
3. This is AND; check: $A = 1, B = 1 \Rightarrow Y = 1$.
4. So the answer is (a) AND ($A = 1, B = 1, Y = 1$).