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NEET 1999 (AIPMT) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from NEET 1999 (AIPMT)

Q54NEET 1999 · AIPMTMedium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

If 1 g1\text{ g} of steam is mixed with 1 g1\text{ g} of ice, then the resultant temperature of the mixture is

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Answer: (c)

  1. Ice needs 80+100=180 cal80 + 100 = 180\text{ cal} to become water at 100∘C100^{\circ}\text{C}.
  2. Steam gives 540 cal540\text{ cal} just by condensing at 100∘C100^{\circ}\text{C}, which is more than 180 cal180\text{ cal}.
  3. So only part of the steam condenses and the mixture stays at 100∘C100^{\circ}\text{C}.
  4. So the answer is (c) 100∘C100^{\circ}\text{C}.
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