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JEE Main 2019 (8 Apr, Shift 1) · Molecular Speeds & Maxwell Distribution

Molecular Speeds & Maxwell Distribution question from JEE Main 2019 (8 Apr, Shift 1)

Q79JEE Main 2019 · 8 APR · SHIFT 1Medium

Molecular Speeds & Maxwell Distribution

If 1022 gas molecules each of mass 10–26 kg collide with a surface (perpendicular to it) elastically per second over an area 1 m2 with a speed 104 m/s, the pressure exerted by the gas molecules will be of the order of:

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Answer: (d)

Each elastic normal hit gives momentum change $2mv$ .
$P = \frac{n \cdot 2mv}{A} = \frac{10^{22}\times2\times10^{-26}\times10^4}{1}$
$P = 2\text{ N/m}^2$
So the answer is (d) $2\text{ N/m}^2$ .

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