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MHT CET 2025 (22 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2025 (22 Apr, Shift 1)

Q39MHT CET 2025 · 22 APR · SHIFT 1Easy

Thermal Radiation: Black Body, Stefan & Wien

If 120 J of thermal energy is incident on area 3 m23\text{ m}^{2}, the amount of heat transmitted is 12 J, coefficient of absorption is 0.6, then the amount of heat reflected is

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Answer: (c)

  1. Absorbed =0.6×120=72= 0.6\times120 = 72 J
  2. Reflected =120−72−12=36= 120 - 72 - 12 = 36 J
  3. So the answer is (c) 36 J.
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