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MHT CET 2026 (13 May, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (13 May, Shift 2)

Q1MHT CET 2026 · 13 MAY · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

If 150150 J of energy is incident on area 2 m22\text{ m}^2 and amount of heat reflected is 1515 J, coefficient of absorption is 0.60.6 the amount of energy transmitted is

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Answer: (b)

  1. a+r+t=1a + r + t = 1; absorbed =0.6×150=90= 0.6\times150 = 90 J
  2. Transmitted =150−90−15=45= 150 - 90 - 15 = 45 J
  3. So the answer is (b) 45 J.
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