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JEE Main 2022 (26 Jul, Shift 2) · Scalar (Dot) Product

Scalar (Dot) Product question from JEE Main 2022 (26 Jul, Shift 2)

Q19JEE Main 2022 · 26 JUL · SHIFT 2Easy

Scalar (Dot) Product

If A⃗=(2i^+3j^−k^) m\vec{A} = (2\hat{i} + 3\hat{j} - \hat{k})\text{ m} and B⃗=(i^+2j^+2k^) m\vec{B} = (\hat{i} + 2\hat{j} + 2\hat{k})\text{ m}. The magnitude of component of vector A⃗\vec{A} along vector B⃗\vec{B} will be ____________ m\text{m}.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

  1. Component of A⃗\vec{A} along B⃗\vec{B} =A⃗⋅B⃗∣B⃗∣= \frac{\vec{A} \cdot \vec{B}}{|\vec{B}|}.
  2. A⃗⋅B⃗=2+6−2=6\vec{A} \cdot \vec{B} = 2 + 6 - 2 = 6, ∣B⃗∣=1+4+4=3|\vec{B}| = \sqrt{1 + 4 + 4} = 3
  3. Component =63=2 m= \frac{6}{3} = 2\text{ m}
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