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NEET 1992 (AIPMT) · Comparing Two Projectiles

Comparing Two Projectiles question from NEET 1992 (AIPMT)

Q30NEET 1992 · AIPMTEasy

Comparing Two Projectiles

If a body AA of mass MM is thrown with velocity vv at an angle of 30∘30^\circ to the horizontal and another body BB of the same mass is thrown with the same speed at an angle of 60∘60^\circ to the horizontal, the ratio of horizontal range of AA to BB will be

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Answer: (b)

  1. R=v2sin⁡2θgR = \frac{v^2\sin 2\theta}{g}, independent of mass.
  2. RARB=sin⁡60∘sin⁡120∘=1\frac{R_A}{R_B} = \frac{\sin 60^\circ}{\sin 120^\circ} = 1
  3. So the answer is (b) 1:11 : 1.
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