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NEET 1997 (AIPMT) · Equations of Kinematics

Equations of Kinematics question from NEET 1997 (AIPMT)

Q42NEET 1997 · AIPMTEasy

Equations of Kinematics

If a car at rest accelerates uniformly to a speed of 144 km/h in 20 sec, it covers a distance of

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Answer: (d)

  1. v=144 km/h=144×518=40 m/sv = 144\text{ km/h} = 144\times\frac{5}{18} = 40\text{ m/s}
  2. s=u+v2 t=0+402×20s = \frac{u + v}{2}\,t = \frac{0 + 40}{2}\times 20
  3. s=400 ms = 400\text{ m}. So the answer is (d).
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