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JEE Main 2002 (AIEEE) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2002 (AIEEE)

Q80JEE Main 2002 · AIEEEEasy

Electric Charge & Coulomb's Law

If a charge $q$ is placed at the center of the line joining two equal charges $Q$ such that the system is in equilibrium then the value of $q$ is

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Answer: (d)

For an end charge $Q$ (separation $2r$ ): $\dfrac{kQ^2}{(2r)^2} + \dfrac{kQq}{r^2} = 0$ .
$q = -\dfrac{Q}{4}$
So the answer is (d) $-Q/4$ .

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