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Electric Potential & Equipotentials question from NEET 2023

Q57NEET 2023Easy

Electric Potential & Equipotentials

If a conducting sphere of radius $R$ is charged. Then the electric field at a distance $r\,(r > R)$ from the centre of the sphere would be, $(V =$ potential on the surface of the sphere)

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Answer: (c)

Surface potential: $V = \frac{Q}{4\pi\varepsilon_0 R} \Rightarrow Q = 4\pi\varepsilon_0 RV$
Outside: $E = \frac{Q}{4\pi\varepsilon_0 r^2} = \frac{RV}{r^2}$
So the answer is (c) $\frac{RV}{r^2}$ .

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