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JEE Main 2025 (23 Jan, Shift 2) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2025 (23 Jan, Shift 2)

Q12JEE Main 2025 · 23 JAN · SHIFT 2Easy

Satellites - Orbital Velocity & Period

If a satellite orbiting the Earth is 9 times closer to the Earth than the Moon, what is the time period of rotation of the satellite? Given rotational time period of Moon =27= 27 days and gravitational attraction between the satellite and the moon is neglected.

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Answer: (d)

  1. Kepler's third law: T∝r3/2T \propto r^{3/2}.
  2. rs=rm9r_s = \frac{r_m}{9}, so Ts=27×(19)3/2=2727=1T_s = 27 \times \left(\frac{1}{9}\right)^{3/2} = \frac{27}{27} = 1 day
  3. So the answer is (d) 1 day.
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