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JEE Main 2005 (AIEEE) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from JEE Main 2005 (AIEEE)

Q77JEE Main 2005 · AIEEEEasy

Periodic Motion & SHM Basics

If a simple harmonic motion is represented by $\frac{d^2x}{dt^2} + \alpha x = 0.$ its time period is

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Answer: (a)

Compare with $\frac{d^2x}{dt^2} + \omega^2 x = 0$ : $\omega = \sqrt{\alpha}$ .
$T = \frac{2\pi}{\omega} = \frac{2\pi}{\sqrt{\alpha}}$ .
So the answer is (a).

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