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MHT CET 2025 (23 Apr, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2025 (23 Apr, Shift 2)

Q18MHT CET 2025 · 23 APR · SHIFT 2Medium

Doppler Effect

If a source emitting waves of frequency ' FF ' moves towards an observer with a velocity V3\frac{V}{3} and the observer moves away from the source with a velocity V4\frac{V}{4}, the apparent frequency as heard by the observer will be ( V=V = velocity of sound)

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Answer: (a)

  1. Observer moving away, source approaching: F′=F V−VoV−VsF' = F\,\dfrac{V - V_o}{V - V_s}.
  2. F′=F V−V/4V−V/3=F 3/42/3=98FF' = F\,\dfrac{V - V/4}{V - V/3} = F\,\dfrac{3/4}{2/3} = \dfrac{9}{8}F
  3. So the answer is (a) 98F\dfrac{9}{8}F.
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