If a wire is stretched to make it 0.1% longer, its resistance will: (a) increase by 0.2% (b) decrease by 0.2% (c) decrease by 0.05% (d) increase by 0.05%

Answer: (a). For small stretching at constant volume, (Δ R)/(R) = 2(Δ l)/(l). (Δ R)/(R) = 2 × 0.1% = 0.2% (increase) So the answer is (a) increase by 0.2%.

If a wire is stretched to make it 0.1% longer, its resistance will: | JEE Main 2011 (AIEEE)

Q59JEE Main 2011 · AIEEEEasy

Ohm's Law, Resistivity & Temperature

If a wire is stretched to make it $0.1\%$ longer, its resistance will:

Show answer and solution

Answer: (a)

For small stretching at constant volume, $\dfrac{\Delta R}{R} = 2\dfrac{\Delta l}{l}$ .
$\dfrac{\Delta R}{R} = 2 \times 0.1\% = 0.2\%$ (increase)
So the answer is (a) increase by $0.2\%$ .

Report a mistake

More questions on Ohm's Law, Resistivity & Temperature

Two conductors have the same resistance at 0 but their temperature coefficients of…JEE Main 2010 (AIEEE)
Statement - 1: The temperature dependence of resistance is usually given as R = R₀(1 + αΔ…JEE Main 2009 (AIEEE)
A wire of a certain material is stretched slowly by ten percent. Its new resistance and…NEET 2008 (AIPMT)
Consider a block of conducting material of resistivity 'ρ' shown in the figure. Current…JEE Main 2008 (AIEEE)
Consider a block of conducting material of resistivity 'ρ' shown in the figure. Current…JEE Main 2008 (AIEEE)
The resistance of a wire is 5 ohm at 50 and 6 ohm at 100. The resistance of the wire at 0…JEE Main 2007 (AIEEE)
A material 'B' has twice the specific resistance of 'A'. A circular wire made of 'B' has…JEE Main 2006 (AIEEE)
The resistance of bulb filament is 100 Ω at a temperature of 100. If its temperature…JEE Main 2006 (AIEEE)

Ohm's Law, Resistivity & Temperature question from JEE Main 2011 (AIEEE)

More questions on Ohm's Law, Resistivity & Temperature