If an electron and a proton having same momentum enter perpendicular to a magnetic field, then (a) curved path of electron and proton will be same (ignoring the sense of revolution) (b) they will move undeflected (c) curved path of electron is more curved than that of the proton (d) path of proton is more curved.

Answer: (a). r = mv/qB = p/qB Same p, same magnitude of charge e, same B ⇒ same radius. They only circle in opposite senses. So the answer is (a) curved paths are the same.

If an electron and a proton having same momentum enter perpendicular… | JEE Main 2002 (AIEEE)

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Moving Charge in a Magnetic Field

If an electron and a proton having same momentum enter perpendicular to a magnetic field, then

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Answer: (a)

$r = \dfrac{mv}{qB} = \dfrac{p}{qB}$
Same $p$ , same magnitude of charge $e$ , same $B$ $\Rightarrow$ same radius.
They only circle in opposite senses.
So the answer is (a) curved paths are the same.

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